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An industrial waste flow of 0.075 MGD requires a chlorine dose of 8.5 mg/K. What should be the chlorinator setting?

  1. 5.3 lbs/24 hr

  2. 10 lbs/24 hr

  3. 7.8 lbs/24 hr

  4. 6.5 lbs/24 hr

The correct answer is: 5.3 lbs/24 hr

To determine the appropriate chlorinator setting for the given industrial waste flow, we first need to convert the required chlorine dose from milligrams per thousand gallons (mg/K) to pounds per day. The flow rate is provided as 0.075 million gallons per day (MGD), which is equivalent to 75,000 gallons per day. The chlorine dose is stated as 8.5 mg/K. To convert this to pounds, we will use the fact that there are 8.34 pounds in one thousand gallons of water. To perform the conversion: 1. Calculate the total chlorine requirement in mg for the daily flow: - Total flow = 75,000 gallons/day - Chlorine dose = 8.5 mg/K (where K = 1,000 gallons) Therefore, Total chlorine (mg) = (75,000 gallons/day / 1,000) * 8.5 mg/K = 75 * 8.5 mg = 637.5 mg/day 2. Now, convert this amount from milligrams to pounds: - 637.5 mg/day is equivalent to 637.5 / 1,000,000 = 0.0006375